Sentence


Parse

I
NP
 
'm
(S[dcl]\NP)/(S[ng]\NP)
 
having
(S[ng]\NP)/NP
 
trouble
N/(S[ng]\NP)
 
reading
(S[ng]\NP)/NP
 
it
NP
 
.
.
 
NP
.
S[ng]\NP
> 0
N
> 0
NP
*
S[ng]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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