Sentence


Parse

I
NP
 
'm
(S[dcl]\NP)/PP
 
not
(S\NP)\(S\NP)
 
(S[dcl]\NP)/PP
< 1×
in
PP/NP
 
the
NP/N
 
habit
N/PP
 
of
PP/(S[ng]\NP)
 
staying
(S[ng]\NP)/PR
 
up
PR
 
S[ng]\NP
> 0
late
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
S[ng]\NP
< 0
PP
> 0
N
> 0
NP
> 0
PP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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