CCGWeb - I'm not married, but my sister is.

(S[dcl]\NP)/(S[adj]\NP)

not

(S\NP)\(S\NP)

(S[dcl]\NP)/(S[adj]\NP)

< ¹_×

married

S[adj]\NP

S[dcl]\NP

> ⁰

S[dcl]

< ⁰

but

conj

NP/(N/PP)

sister

N/PP

> ⁰

S[dcl]\NP

S[dcl]

< ⁰

S[dcl]\S[dcl]

∨

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="I" data-from="0" data-to="1" data-cat="NP">
<tr><td class="token">I</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[adj]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="'m" data-from="1" data-to="3" data-cat="(S[dcl]\NP)/(S[adj]\NP)">
<tr><td class="token">'m</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="not" data-from="4" data-to="7" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">not</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[adj]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[adj]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="married" data-from="8" data-to="15" data-cat="S[adj]\NP">
<tr><td class="token">married</td></tr>
<tr><td class="cat" tabindex="0">S[adj]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="," data-from="15" data-to="16" data-cat=",">
<tr><td class="token">,</td></tr>
<tr><td class="cat" tabindex="0">,</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[adj]\NP</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="but" data-from="17" data-to="20" data-cat="conj">
<tr><td class="token">but</td></tr>
<tr><td class="cat" tabindex="0">conj</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="my" data-from="21" data-to="23" data-cat="NP/(N/PP)">
<tr><td class="token">my</td></tr>
<tr><td class="cat" tabindex="0">NP/(N/PP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="sister" data-from="24" data-to="30" data-cat="N/PP">
<tr><td class="token">sister</td></tr>
<tr><td class="cat" tabindex="0">N/PP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="31" data-to="33" data-cat="S[dcl]\NP">
<tr><td class="token">is</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="33" data-to="34" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\S[dcl]</div>
<div class="rule" title="Conjunction">∨</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm13}{I}{\catNP}{} \&
		\lexnode*{idm39}{'m}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm53}{not}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm74}{married}{\catS[adj]\?\catNP}{} \&
		\lexnode*{idm84}{,}{\cat,}{} \&
		\lexnode*{idm99}{but}{\catconj}{} \&
		\lexnode*{idm117}{my}{\catNP/(\catN/\catPP)}{} \&
		\lexnode*{idm129}{sister}{\catN/\catPP}{} \&
		\lexnode*{idm146}{is}{\catS[dcl]\?\catNP}{} \&
		\lexnode*{idm156}{.}{\cat.}{} \\
	};
	\binnode*{idm28}{idm39-cat}{idm53-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{}
	\binnode*{idm67}{idm74-cat}{idm84-cat}{.}{\catS[adj]\?\catNP}{}
	\binnode*{idm21}{idm28}{idm67}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm8}{idm13-cat}{idm21}{\BC{0}}{\catS[dcl]}{}
	\binnode*{idm112}{idm117-cat}{idm129-cat}{\FC{0}}{\catNP}{}
	\binnode*{idm139}{idm146-cat}{idm156-cat}{.}{\catS[dcl]\?\catNP}{}
	\binnode*{idm107}{idm112}{idm139}{\BC{0}}{\catS[dcl]}{}
	\binnode*{idm92}{idm99-cat}{idm107}{\wedge}{\catS[dcl]\?\catS[dcl]}{}
	\binnode*{idm3}{idm8}{idm92}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations