Sentence


Parse

I
NP
 
'm
(S[dcl]\NP)/(S[adj]\NP)
 
sure
(S[adj]\NP)/S[dcl]
 
Tom
N
 
NP
*
wo
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
be
(S[b]\NP)/(S[adj]\NP)
 
first
S[adj]\NP
 
.
.
 
S[adj]\NP
.
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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