Sentence


Parse

I
NP
 
've
(S[dcl]\NP)/(S[pt]\NP)
 
got
((S[pt]\NP)/(S[to]\NP))/NP
 
nothing
NP
 
(S[pt]\NP)/(S[to]\NP)
> 0
to
(S[to]\NP)/(S[b]\NP)
 
do
(S[b]\NP)/PP
 
with
PP/NP
 
it
NP
 
PP
> 0
.
.
 
PP
.
S[b]\NP
> 0
S[to]\NP
> 0
S[pt]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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