Sentence


Parse

I
NP
 
've
(S[dcl]\NP)/(S[pt]\NP)
 
had
(S[pt]\NP)/NP
 
enough
N
 
NP
*
S[pt]\NP
> 0
already
(S\NP)\(S\NP)
 
!
.
 
(S\NP)\(S\NP)
.
S[pt]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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