Sentence


Parse

I
NP
 
've
(S[dcl]\NP)/NP
 
nothing
NP
 
S[dcl]\NP
> 0
to
(S[to]\NP)/(S[b]\NP)
 
do
S[b]\NP
 
S[to]\NP
> 0
S/S
*
today
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
(S\NP)\(S\NP)
> n
S[dcl]\NP
< 0
S[dcl]
< 0

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