Sentence


Parse

I
NP
 
ca
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
make
(S[b]\NP)/NP
 
head
N
 
NP
*
nor
conj
 
tail
N/PP
 
of
PP/NP
 
it
NP
 
PP
> 0
.
.
 
PP
.
N
> 0
NP
*
NP\NP
NP
< 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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