CCGWeb - I can't stand it anymore.

(S[dcl]\NP)/(S[b]\NP)

n't

(S\NP)\(S\NP)

(S[dcl]\NP)/(S[b]\NP)

< ¹_×

stand

(S[b]\NP)/NP

S[b]\NP

> ⁰

S[dcl]\NP

> ⁰

anymore

(S\NP)\(S\NP)

S[dcl]\NP

< ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="I" data-from="0" data-to="1" data-cat="NP">
<tr><td class="token">I</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="ca" data-from="2" data-to="4" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr><td class="token">ca</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="4" data-to="7" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">n't</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[b]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="stand" data-from="8" data-to="13" data-cat="(S[b]\NP)/NP">
<tr><td class="token">stand</td></tr>
<tr><td class="cat" tabindex="0">(S[b]\NP)/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="it" data-from="14" data-to="16" data-cat="NP">
<tr><td class="token">it</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="anymore" data-from="17" data-to="24" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">anymore</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="24" data-to="25" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{I}{\catNP}{} \&
		\lexnode*{idm41}{ca}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \&
		\lexnode*{idm55}{n't}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm76}{stand}{(\catS[b]\?\catNP)/\catNP}{} \&
		\lexnode*{idm88}{it}{\catNP}{} \&
		\lexnode*{idm107}{anymore}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm121}{.}{\cat.}{} \\
	};
	\binnode*{idm30}{idm41-cat}{idm55-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{}
	\binnode*{idm69}{idm76-cat}{idm88-cat}{\FC{0}}{\catS[b]\?\catNP}{}
	\binnode*{idm23}{idm30}{idm69}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm96}{idm107-cat}{idm121-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm16}{idm23}{idm96}{\BC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations