Sentence


Parse

I
NP
 
counted
(S[dcl]\NP)/PP
 
to
PP/NP
 
three
N
 
NP
*
PP
> 0
S[dcl]\NP
> 0
and
conj
 
then
(S\NP)/(S\NP)
 
plunged
(S[dcl]\NP)/PP
 
into
PP/NP
 
the
NP/N
 
water
N
 
NP
> 0
.
.
 
NP
.
PP
> 0
S[dcl]\NP
> 0
S[dcl]\NP
> 0
(S[dcl]\NP)\(S[dcl]\NP)
S[dcl]\NP
< 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.