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I
NP
 
did
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
know
(S[b]\NP)/S[qem]
 
whether
S[qem]/S[dcl]
 
Tom
N
 
NP
*
would
(S[dcl]\NP)/(S[b]\NP)
 
be
(S[b]\NP)/(S[pss]\NP)
 
allowed
(S[pss]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
do
(S[b]\NP)/NP
 
that
NP
 
or
conj
 
not
NP
 
.
.
 
NP
.
NP\NP
NP
< 0
S[b]\NP
> 0
S[to]\NP
> 0
S[pss]\NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[qem]
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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