Sentence


Parse

I
NP
 
returned
(S[dcl]\NP)/PP
 
from
PP/NP
 
Boston
N
 
NP
*
PP
> 0
S[dcl]\NP
> 0
on
((S\NP)\(S\NP))/NP
 
October
N/N
 
20th
N
 
N
> 0
NP
*
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0

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