CCGWeb - I still don't know yet.

still

(S\NP)/(S\NP)

(S[dcl]\NP)/(S[b]\NP)

n't

(S\NP)\(S\NP)

(S[dcl]\NP)/(S[b]\NP)

< ¹_×

know

S[b]\NP

yet

(S\NP)\(S\NP)

S[b]\NP

< ⁰

S[dcl]\NP

> ⁰

S[dcl]\NP

> ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="I" data-from="0" data-to="1" data-cat="NP">
<tr><td class="token">I</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="still" data-from="2" data-to="7" data-cat="(S\NP)/(S\NP)">
<tr><td class="token">still</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)/(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="do" data-from="8" data-to="10" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr><td class="token">do</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="10" data-to="13" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">n't</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/(S[b]\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="know" data-from="14" data-to="18" data-cat="S[b]\NP">
<tr><td class="token">know</td></tr>
<tr><td class="cat" tabindex="0">S[b]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="yet" data-from="19" data-to="22" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">yet</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="22" data-to="23" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{I}{\catNP}{} \&
		\lexnode*{idm23}{still}{(\catS\?\catNP)/(\catS\?\catNP)}{} \&
		\lexnode*{idm55}{do}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \&
		\lexnode*{idm69}{n't}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm90}{know}{\catS[b]\?\catNP}{} \&
		\lexnode*{idm111}{yet}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm125}{.}{\cat.}{} \\
	};
	\binnode*{idm44}{idm55-cat}{idm69-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{}
	\binnode*{idm100}{idm111-cat}{idm125-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm83}{idm90-cat}{idm100}{\BC{0}}{\catS[b]\?\catNP}{}
	\binnode*{idm37}{idm44}{idm83}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm16}{idm23-cat}{idm37}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations