Sentence


Parse

I
NP
 
talk
(S[dcl]\NP)/PP
 
to
PP/NP
 
my
NP/(N/PP)
 
clients
N/PP
 
NP
> 0
PP
> 0
S[dcl]\NP
> 0
in
((S\NP)\(S\NP))/NP
 
Berber
N
 
NP
*
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0

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