Sentence


Parse

I
NP
 
think
(S[dcl]\NP)/(S[adj]\NP)
 
so
S[adj]\NP
 
as
((S\NP)\(S\NP))/((S\NP)\(S\NP))
 
well
(S\NP)\(S\NP)
 
.
.
 
(S\NP)\(S\NP)
.
(S\NP)\(S\NP)
> 0
S[adj]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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