Sentence


Parse

I
NP
 
was
(S[dcl]\NP)/(S[adj]\NP)
 
totally
(S[adj]\NP)/(S[adj]\NP)
 
right
S[adj]\NP
 
S[adj]\NP
> 0
.
.
 
S[adj]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

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