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I
NP
 
will
(S[dcl]\NP)/(S[b]\NP)
 
write
(S[b]\NP)/NP
 
him
NP
 
S[b]\NP
> 0
S[dcl]\NP
> 0
when
((S\NP)\(S\NP))/S[dcl]
 
I
NP
 
know
(S[dcl]\NP)/NP
 
his
NP/(N/PP)
 
address
N/PP
 
NP
> 0
.
.
 
NP
.
S[dcl]\NP
> 0
S[dcl]
< 0
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
S[dcl]
< 0

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