Sentence


Parse

If
(S/S)/S[dcl]
 
I
NP
 
knew
(S[dcl]\NP)/NP
 
his
NP/(N/PP)
 
address
N/PP
 
NP
> 0
,
,
 
NP
.
S[dcl]\NP
> 0
S[dcl]
< 0
S/S
> 0
I
NP
 
would
(S[dcl]\NP)/(S[b]\NP)
 
write
(S[b]\NP)/PP
 
to
PP/NP
 
him
NP
 
PP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]
> 0
.
.
 
S[dcl]
.

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