Sentence


Parse

If
(S/S)/S[dcl]
 
we
NP
 
repeat
(S[dcl]\NP)/NP
 
a
NP/N
 
lie
N
 
NP
> 0
S[dcl]\NP
> 0
again
(S\NP)\(S\NP)
 
and
conj
 
again
(S\NP)\(S\NP)
 
((S\NP)\(S\NP))\((S\NP)\(S\NP))
(S\NP)\(S\NP)
< 0
S[dcl]\NP
< 0
,
,
 
S[dcl]\NP
.
S[dcl]
< 0
S/S
> 0
it
NP[expl]
 
will
(S[dcl]\NP)/(S[b]\NP)
 
not
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
become
(S[b]\NP)/(S[adj]\NP)
 
true
S[adj]\NP
 
,
,
 
S[adj]\NP
.
but
conj
 
more
S[adj]\NP
 
(S[adj]\NP)\(S[adj]\NP)
S[adj]\NP
< 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]
> 0
and
conj
 
more
N/N
 
people
N
 
N
> 0
NP
*
will
(S[dcl]\NP)/(S[b]\NP)
 
believe
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
.
.
 
S[b]\NP
.
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]\S[dcl]
S[dcl]
< 0

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