Sentence


Parse

If
(S/S)/S[dcl]
 
I
NP
 
'd
(S[dcl]\NP)/(S[pt]\NP)
 
known
(S[pt]\NP)/NP
 
her
NP/(N/PP)
 
address
N/PP
 
NP
> 0
,
,
 
I
NP
 
NP\NP
NP
< 0
S[pt]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S/S
> 0
would
(S[dcl]\NP)/(S[b]\NP)
 
've
(S[b]\NP)/(S[pt]\NP)
 
written
(S[pt]\NP)/NP
 
(S[b]\NP)/NP
> 1
(S[dcl]\NP)/NP
> 1
her
NP
 
S[X]/(S[X]\NP)
T >
a
NP/N
 
letter
N
 
NP
> 0
.
.
 
NP
.
(S[X]\NP)\((S[X]\NP)/NP)
T <
S[X]\((S[X]\NP)/NP)
> 1×
S[dcl]
< 0
S[dcl]
> 0

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