Sentence


Parse

If
(S/S)/S[dcl]
 
I
NP
 
had
(S[dcl]\NP)/(S[pt]\NP)
 
known
(S[pt]\NP)/NP
 
his
NP/(N/PP)
 
address
N/PP
 
,
,
 
N/PP
.
NP
> 0
S[pt]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S/S
> 0
I
NP
 
would
(S[dcl]\NP)/(S[b]\NP)
 
have
(S[b]\NP)/(S[pt]\NP)
 
written
(S[pt]\NP)/PP
 
to
PP/NP
 
him
NP
 
PP
> 0
.
.
 
PP
.
S[pt]\NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[dcl]
> 0

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