Sentence


Parse

Is
(S[q]/(S[adj]\NP))/NP
 
it
NP[expl]
 
S[q]/(S[adj]\NP)
> 0
possible
(S[adj]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
get
(S[b]\NP)/PP
 
to
PP/NP
 
Boston
N
 
NP
*
PP
> 0
S[b]\NP
> 0
by
((S\NP)\(S\NP))/NP
 
train
N
 
NP
*
?
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[to]\NP
> 0
S[adj]\NP
> 0
S[q]
> 0

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