Sentence


Parse

Is
(S[q]/NP)/NP
 
it
NP[expl]
 
S[q]/NP
> 0
true
S[adj]\NP
 
N/N
*
you
NP
 
S[X]/(S[X]\NP)
T >
're
(S[dcl]\NP)/(S[ng]\NP)
 
moving
(S[ng]\NP)/PP
 
to
PP/NP
 
(S[ng]\NP)/NP
> 1
(S[dcl]\NP)/NP
> 1
S[dcl]/NP
> 1
N\N
*
N/N
< 1×
Boston
N
 
N
> 0
NP
*
?
.
 
NP
.
S[q]
> 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.