Sentence


Parse

It
NP
 
'll
(S[dcl]\NP)/(S[b]\NP)
 
take
(S[b]\NP)/(S[adj]\NP)
 
longer
(S\NP)\(S\NP)
 
(S[b]\NP)/(S[adj]\NP)
< 1×
to
(S[to]\NP)/(S[b]\NP)
 
tell
((S[b]\NP)/S[qem])/NP
 
you
NP
 
(S[b]\NP)/S[qem]
> 0
how
S[qem]/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
do
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
S[to]\NP
> 0
S[qem]
> 0
S[b]\NP
> 0
S[to]\NP
> 0
than
((S\NP)\(S\NP))/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
just
(S\NP)/(S\NP)
 
go
S[b]\NP
 
S[b]\NP
> 0
S[to]\NP
> 0
(S\NP)\(S\NP)
> 0
S[to]\NP
< 0
S/S
*
ahead
S[adj]\NP
 
S[adj]\NP
> 1×
S[b]\NP
> 0
and
conj
 
do
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
myself
(S\NP)\(S\NP)
 
S[b]\NP
< 0
.
.
 
S[b]\NP
.
(S[b]\NP)\(S[b]\NP)
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0

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