Sentence


Parse

It
NP[expl]
 
's
((S[dcl]\NP[expl])/(S[to]\NP))/(S[adj]\NP)
 
up
(S[adj]\NP)/PP
 
to
PP/NP
 
Tom
N
 
NP
*
PP
> 0
S[adj]\NP
> 0
(S[dcl]\NP[expl])/(S[to]\NP)
> 0
to
(S[to]\NP)/(S[b]\NP)
 
decide
S[b]\NP
 
S[to]\NP
> 0
.
.
 
S[to]\NP
.
S[dcl]\NP[expl]
> 0
S[dcl]
< 0

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