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It
NP
 
is
(S[dcl]\NP)/NP
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/NP
< 1×
as
(S[adj]\NP)/(S[adj]\NP)
 
bad
S[adj]\NP
 
S[adj]\NP
> 0
as
((S\NP)\(S\NP))/NP
 
all
NP
 
(S\NP)\(S\NP)
> 0
S[adj]\NP
< 0
N/N
*
that
N
 
N
> 0
NP
*
.
.
 
NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

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