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It
NP
 
is
(S[dcl]\NP)/PP
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/PP
< 1×
like
PP/NP
 
that
NP
 
PP
> 0
.
.
 
PP
.
S[dcl]\NP
> 0
S[dcl]
< 0

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