Sentence


Parse

Leave
((S[b]\NP)/PP)/NP
 
it
NP
 
(S[b]\NP)/PP
> 0
in
PP/NP
 
my
NP/(N/PP)
 
hands
N/PP
 
NP
> 0
.
.
 
NP
.
PP
> 0
S[b]\NP
> 0

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