Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
's
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
get
(S[b]\NP)/(S[ng]\NP)
 
going
S[ng]\NP
 
S[b]\NP
> 0
S[b]\NP
> 0
.
.
 
S[b]\NP
.

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