Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
's
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
get
(S[b]\NP)/(S[pss]\NP)
 
started
S[pss]\NP
 
!
.
 
S[pss]\NP
.
S[b]\NP
> 0
S[b]\NP
> 0

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