Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
's
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
get
(S[b]\NP)/NP
 
this
NP/N
 
show
N/PP
 
on
PP/NP
 
the
NP/N
 
road
N
 
NP
> 0
PP
> 0
N
> 0
NP
> 0
.
.
 
NP
.
S[b]\NP
> 0
S[b]\NP
> 0

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