Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
's
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
go
S[b]\NP
 
S[b]\NP
> 0
and
conj
 
see
(S[b]\NP)/NP
 
Tom
N
 
NP
*
.
.
 
NP
.
S[b]\NP
> 0
(S[b]\NP)\(S[b]\NP)
S[b]\NP
< 0

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