Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
's
N
 
NP
*
(S[b]\NP)/(S[b]\NP)
> 0
leave
(S[b]\NP)/NP
 
it
NP
 
S[b]\NP
> 0
at
((S\NP)\(S\NP))/NP
 
that
NP
 
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[b]\NP
< 0
S[b]\NP
> 0

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