Sentence


Parse

Let
((S[b]\NP)/(S[b]\NP))/NP
 
me
NP
 
(S[b]\NP)/(S[b]\NP)
> 0
know
(S[b]\NP)/S[qem]
 
when
S[qem]/S[dcl]
 
you
NP
 
'll
(S[dcl]\NP)/(S[b]\NP)
 
return
(S[b]\NP)/NP
 
home
N
 
NP
*
.
.
 
NP
.
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[qem]
> 0
S[b]\NP
> 0
S[b]\NP
> 0

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