CCGWeb - Mary is poor, isn't she?

Mary

(S[dcl]\NP)/(S[adj]\NP)

poor

S[adj]\NP

S[dcl]\NP

> ⁰

(S[dcl]\NP)/NP

n't

S\S

(S[dcl]\NP)/NP

< ⁿ

she

S[dcl]\NP

> ⁰

(S[dcl]\NP)\(S[dcl]\NP)

∨

S[dcl]\NP

< ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent unaryrule" data-cat="NP">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="Mary" data-from="0" data-to="4" data-cat="N">
<tr><td class="token">Mary</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Type Changing">
									*
								</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="5" data-to="7" data-cat="(S[dcl]\NP)/(S[adj]\NP)">
<tr><td class="token">is</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[adj]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="poor" data-from="8" data-to="12" data-cat="S[adj]\NP">
<tr><td class="token">poor</td></tr>
<tr><td class="cat" tabindex="0">S[adj]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)\(S[dcl]\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="," data-from="12" data-to="13" data-cat=",">
<tr><td class="token">,</td></tr>
<tr><td class="cat" tabindex="0">,</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="14" data-to="16" data-cat="(S[dcl]\NP)/NP">
<tr><td class="token">is</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="16" data-to="19" data-cat="S\S">
<tr><td class="token">n't</td></tr>
<tr><td class="cat" tabindex="0">S\S</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/NP</div>
<div class="rule" title="Backward Composition">&lt; <sup><i>n</i></sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="she" data-from="20" data-to="23" data-cat="NP">
<tr><td class="token">she</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="?" data-from="23" data-to="24" data-cat=".">
<tr><td class="token">?</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)\(S[dcl]\NP)</div>
<div class="rule" title="Conjunction">∨</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm11}{Mary}{\catN}{} \&
		\lexnode*{idm33}{is}{(\catS[dcl]\?\catNP)/(\catS[adj]\?\catNP)}{} \&
		\lexnode*{idm47}{poor}{\catS[adj]\?\catNP}{} \&
		\lexnode*{idm68}{,}{\cat,}{} \&
		\lexnode*{idm92}{is}{(\catS[dcl]\?\catNP)/\catNP}{} \&
		\lexnode*{idm104}{n't}{\catS\?\catS}{} \&
		\lexnode*{idm119}{she}{\catNP}{} \&
		\lexnode*{idm127}{?}{\cat.}{} \\
	};
	\unnode*{idm8}{idm11-cat}{*}{\catNP}{}
	\binnode*{idm26}{idm33-cat}{idm47-cat}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm83}{idm92-cat}{idm104-cat}{\BC{n}}{(\catS[dcl]\?\catNP)/\catNP}{}
	\binnode*{idm114}{idm119-cat}{idm127-cat}{.}{\catNP}{}
	\binnode*{idm76}{idm83}{idm114}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm57}{idm68-cat}{idm76}{\wedge}{(\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP)}{}
	\binnode*{idm19}{idm26}{idm57}{\BC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm3}{idm8}{idm19}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

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