Sentence


Parse

My
NP/(N/PP)
 
bag
N/PP
 
NP
> 0
is
(S[dcl]\NP)/(S[adj]\NP)
 
missing
S[adj]\NP
 
S[dcl]\NP
> 0
S[dcl]
< 0
.
.
 
S[dcl]
.

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