Sentence


Parse

My
NP/N
 
computer
N
 
NP
> 0
does
(S[dcl]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[dcl]\NP)/(S[b]\NP)
< 1×
seem
(S[b]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
be
(S[b]\NP)/(S[ng]\NP)
 
connecting
(S[ng]\NP)/PP
 
to
PP/NP
 
the
NP/N
 
printer
N
 
NP
> 0
.
.
 
NP
.
PP
> 0
S[ng]\NP
> 0
S[b]\NP
> 0
S[to]\NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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