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No
NP/N
 
one
N
 
NP
> 0
knows
(S[dcl]\NP)/S[qem]
 
when
S[qem]/S[dcl]
 
this
NP/N
 
custom
N
 
NP
> 0
came
(S[dcl]\NP)/PP
 
into
PP/NP
 
existence
N
 
NP
*
.
.
 
NP
.
PP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0
S[qem]
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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