Sentence


Parse

Such
NP/NP
 
a
NP/N
 
man
N
 
NP
> 0
NP
> 0
is
(S[dcl]\NP)/(S[pss]\NP)
 
bound
(S[pss]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
fail
S[b]\NP
 
S[to]\NP
> 0
.
.
 
S[to]\NP
.
S[pss]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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