Sentence


Parse

That
NP
 
's
(S[dcl]\NP)/(S[adj]\NP)
 
up
(S[adj]\NP)/PP
 
to
PP/NP
 
Tom
N
 
NP
*
.
.
 
NP
.
PP
> 0
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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