Sentence


Parse

That
NP
 
's
((S[dcl]\NP)/PP)/NP
 
Greek
N
 
NP
*
(S[dcl]\NP)/PP
> 0
to
PP/NP
 
me
NP
 
.
.
 
NP
.
PP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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