Sentence


Parse

That
NP
 
's
(S[dcl]\NP)/NP
 
just
N/N
 
fine
N
 
with
(N\N)/NP
 
me
NP
 
N\N
> 0
.
.
 
N\N
.
N
< 0
N
> 0
NP
*
S[dcl]\NP
> 0
S[dcl]
< 0

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