Sentence


Parse

That
NP
 
's
(S[dcl]\NP)/NP
 
not
(S\NP)\(S\NP)
 
(S[dcl]\NP)/NP
< 1×
what
NP/(S[dcl]/NP)
 
I
NP
 
S[X]/(S[X]\NP)
T >
understand
(S[dcl]\NP)/NP
 
.
.
 
(S[dcl]\NP)/NP
.
S[dcl]/NP
> 1
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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