Sentence


Parse

That
NP
 
's
(S[dcl]\NP)/NP
 
the
NP/N
 
way
N/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
go
S[b]\NP
 
S[to]\NP
> 0
!
.
 
S[to]\NP
.
N
> 0
NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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