Sentence


Parse

The
NP/N
 
only
N/N
 
one
N
 
N
> 0
who
(N\N)/(S[dcl]\NP)
 
can
(S[dcl]\NP)/(S[b]\NP)
 
solve
(S[b]\NP)/NP
 
this
NP/N
 
problem
N
 
NP
> 0
S[b]\NP
> 0
S[dcl]\NP
> 0
N\N
> 0
N
< 0
NP
> 0
is
(S[dcl]\NP)/NP
 
you
NP
 
.
.
 
NP
.
S[dcl]\NP
> 0
S[dcl]
< 0

Use with der.css.

Use with ccgsym.sty and tikzlibraryccgder.code.tex.