Sentence


Parse

There
NP[thr]
 
's
(S[dcl]\NP[thr])/NP
 
no
NP/N
 
question
N/PP
 
about
PP/NP
 
that
NP
 
!
.
 
NP
.
PP
> 0
N
> 0
NP
> 0
S[dcl]\NP[thr]
> 0
S[dcl]
< 0

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