Sentence


Parse

There
NP[thr]
 
's
(S[dcl]\NP[thr])/NP
 
nothing
N
 
wrong
S[adj]\NP
 
N\N
*
N
< 0
NP
*
S[dcl]\NP[thr]
> 0
with
((S\NP)\(S\NP))/NP
 
that
NP
 
.
.
 
NP
.
(S\NP)\(S\NP)
> 0
S[dcl]\NP[thr]
< 0
S[dcl]
< 0

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