Sentence


Parse

There
NP[thr]
 
have
(S[dcl]\NP[thr])/(S[pt]\NP)
 
been
(S[pt]\NP)/NP
 
some
NP/N
 
changes
N
 
NP
> 0
.
.
 
NP
.
S[pt]\NP
> 0
S[dcl]\NP[thr]
> 0
S[dcl]
< 0

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