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There

NP[thr]

(S[dcl]\NP[thr])/NP

n't

(S\NP)\(S\NP)

(S[dcl]\NP[thr])/NP

< ¹_×

any

NP/N

problem

> ⁰

S[dcl]\NP[thr]

> ⁰

((S\NP)\(S\NP))/NP

all

(S\NP)\(S\NP)

> ⁰

(S\NP)\(S\NP)

S[dcl]\NP[thr]

< ⁰

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="There" data-from="0" data-to="5" data-cat="NP[thr]">
<tr><td class="token">There</td></tr>
<tr><td class="cat" tabindex="0">NP[thr]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP[thr]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]\NP[thr]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP[thr])/NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="is" data-from="6" data-to="8" data-cat="(S[dcl]\NP[thr])/NP">
<tr><td class="token">is</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP[thr])/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="n't" data-from="8" data-to="11" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">n't</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP[thr])/NP</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="any" data-from="12" data-to="15" data-cat="NP/N">
<tr><td class="token">any</td></tr>
<tr><td class="cat" tabindex="0">NP/N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="problem" data-from="16" data-to="23" data-cat="N">
<tr><td class="token">problem</td></tr>
<tr><td class="cat" tabindex="0">N</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP[thr]</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="at" data-from="24" data-to="26" data-cat="((S\NP)\(S\NP))/NP">
<tr><td class="token">at</td></tr>
<tr><td class="cat" tabindex="0">((S\NP)\(S\NP))/NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="all" data-from="27" data-to="30" data-cat="NP">
<tr><td class="token">all</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="30" data-to="31" data-cat=".">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP[thr]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm8}{There}{\catNP[thr]}{} \&
		\lexnode*{idm39}{is}{(\catS[dcl]\?\catNP[thr])/\catNP}{} \&
		\lexnode*{idm51}{n't}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm70}{any}{\catNP/\catN}{} \&
		\lexnode*{idm80}{problem}{\catN}{} \&
		\lexnode*{idm110}{at}{((\catS\?\catNP)\?(\catS\?\catNP))/\catNP}{} \&
		\lexnode*{idm126}{all}{\catNP}{} \&
		\lexnode*{idm134}{.}{\cat.}{} \\
	};
	\binnode*{idm30}{idm39-cat}{idm51-cat}{\BXC{1}}{(\catS[dcl]\?\catNP[thr])/\catNP}{}
	\binnode*{idm65}{idm70-cat}{idm80-cat}{\FC{0}}{\catNP}{}
	\binnode*{idm23}{idm30}{idm65}{\FC{0}}{\catS[dcl]\?\catNP[thr]}{}
	\binnode*{idm99}{idm110-cat}{idm126-cat}{\FC{0}}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm88}{idm99}{idm134-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm16}{idm23}{idm88}{\BC{0}}{\catS[dcl]\?\catNP[thr]}{}
	\binnode*{idm3}{idm8-cat}{idm16}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations