Sentence


Parse

They
NP
 
know
S[dcl]\NP
 
very
((S\NP)\(S\NP))/((S\NP)\(S\NP))
 
well
(S\NP)\(S\NP)
 
(S\NP)\(S\NP)
> 0
S[dcl]\NP
< 0
who
conj
 
we
NP
 
are
(S[dcl]\NP)/NP
 
,
,
 
(S[dcl]\NP)/NP
.
and
conj
 
what
NP/(S[dcl]/NP)
 
we
NP
 
S[X]/(S[X]\NP)
T >
can
(S[dcl]\NP)/(S[b]\NP)
 
do
(S[b]\NP)/NP
 
.
.
 
(S[b]\NP)/NP
.
(S[dcl]\NP)/NP
> 1
S[dcl]/NP
> 1
NP
> 0
NP\NP
(S[dcl]\NP)\NP
> 1×
S[dcl]\NP
< 0
(S[dcl]\NP)\(S[dcl]\NP)
S[dcl]\NP
< 0
S[dcl]
< 0

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